sqlsrv_fetch_array expects parameter 1 to be resou
Explanations: The reason for your error is that sqlsrv_query() returns false , which means that your statement is not executed correctly:.,Error sqlsrv_fetch_array() expects parameter 1 to be resource, boolean given means that sqlsrv_query() returns false instead of statement ...
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sqlsrv_fetch_array() expects parameter 1 to be resource ...
Your query failed. This causes sqlsrv_query() to return false. Your error in your query is an errant comma: $sql = SELECT first_col, s_col, ... https://stackoverflow.com sqlsrv_fetch_array() expects parameter 1 to be resource when ...
Explanations: The reason for your error is that sqlsrv_query() returns false , which means that your statement is not executed correctly:. https://stackoverflow.com (sqlsrv_fetch_array() expects parameter 1 to be resource ...
Error sqlsrv_fetch_array() expects parameter 1 to be resource, boolean given means that sqlsrv_query() returns false instead of statement ... https://stackoverflow.com sqlsrv_fetch_array() expects parameter 1 to ... - Stack Overflow
According to its documentation, sqlsrv_query() returns false if it gets an error or a statement resource on success. https://stackoverflow.com PHP Search Query Error: sqlsrv_fetch_array() expects ...
2017年12月4日 — ... sqlsrv_fetch_array() expects parameter 1 to be resource, boolean ... (which you don't check for) and passes it to sqlsrv_fetch_array . https://stackoverflow.com sqlsrv_fetch_array() expects parameter 1 to be resource
Do a print_r($row); just after the sqlsrv_fetch_array() call to check what $row contains exactly. I guess you have a case sensitivity issue ... https://stackoverflow.com sqlsrv_fetch_array() expects parameter 1 to be resource, bool ...
Probably there's a problem with your query. A notice that you put a quote (') before r.Report_Id and after it: $sql2 = SELECT DISTINCT 'r. https://stackoverflow.com |