self adjoint form
在數學裏，作用於一個有限維的么正空間，一個自伴算子（self-adjoint operator）等於自己的伴隨算子；等價地說，在一組單位酉正交基下，表達自伴算子的矩陣是埃爾米 ... ,In mathematics, a self-adjoint operator (or Hermitian operator) on a finite-dimensional complex ... defined as follows: Let (X, Σ, μ) be a countably additive measure space and f a real-valued measurable function on X. An operator T of the form.
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 self adjoint form 相關參考資料
Self-Adjoint -- from Wolfram MathWorld
Self-Adjoint. Consider a second-order differential operator. L^~u(x)=p_0(d^2u)/ ... https://mathworld.wolfram.com 自伴算子- 維基百科，自由的百科全書 - Wikipedia
在數學裏，作用於一個有限維的么正空間，一個自伴算子（self-adjoint operator）等於自己的伴隨算子；等價地說，在一組單位酉正交基下，表達自伴算子的矩陣是埃爾米 ... https://zh.wikipedia.org Self-adjoint operator - Wikipedia
In mathematics, a self-adjoint operator (or Hermitian operator) on a finite-dimensional complex ... defined as follows: Let (X, Σ, μ) be a countably additive measure space and f a real-valued measurab... https://en.wikipedia.org Self-adjoint - Wikipedia
In functional analysis, a linear operator A on a Hilbert space is called self-adjoint if it is equal to its own adjoint A∗ and that the domain of A is the same as that of ... https://en.wikipedia.org How to write a non-homogeneous equation in self-adjoint form ...
Suppose you have. y″+fy′+gy=h. By means of an integrating factor, μ=exp(∫f), we obtain. μ(y″+fy′+gy)=μh⟺(μy′)′+gμy=μh. Thus, in your example, we ... https://math.stackexchange.com Find the self-adjoint form of the ODE - Math Stack Exchange
Divide by x and find (xy′(x))′+μxy(x)=0. In general, you compute the derivatives in the self-adjoint form and then compare coefficients, ... https://math.stackexchange.com Self-adjoint differential equation - Encyclopedia of Mathematics
... and the bar denotes complex conjugation. The left-hand side of every self-adjoint differential equation is a sum of expressions of the form ... https://www.encyclopediaofmath Self-adjoint differential equations - Physics Pages
Not every ODE is written in terms of a self-adjoint operator, but we can always transform the equation in self-adjoint form, assuming that p0 = 0. http://physicspages.com 1 Introduction 2 Self-adjoint Operators - Caltech High Energy ...
Theorem: The eigenvectors of a compact, self-adjoint operator form a com- plete set (when we include eigenvectors corresponding to zero eigenval- ues). http://www.hep.caltech.edu |