php switch case return
6 Answers. It's perfectly valid to leave out the break when you return from a switch . But it's fairly common practise to add explicit break s to every case as a defensive programming practise. The idea is that should you later change your code i, And after the switch statement you just have return $result , using return ... (for reference: http://php.net/manual/en/function.return.php says:.
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switch - Manual - PHP
The switch statement is similar to a series of IF statements on the same expression. In many ... case 0: return 'Monkey'; // Years 0, 12, 1200, 2004... case 1: return ... https://www.php.net PHP Coding styles return; in switchcase - Stack Overflow
6 Answers. It's perfectly valid to leave out the break when you return from a switch . But it's fairly common practise to add explicit break s to every case as a defensive programming practis... https://stackoverflow.com Do you need break in switch when return is used? - Stack ...
And after the switch statement you just have return $result , using return ... (for reference: http://php.net/manual/en/function.return.php says:. https://stackoverflow.com php - Do you need break in switch when return is used ...
7 Answers. Yes, you can use return instead of break ... break is optional and is used to prevent "falling" through all the other case statements. So return can be used in a similar fashion,... https://stackoverflow.com PHP switch case multiple returns - Stack Overflow
Your code is a bit messy, too much if/elseif/else makes code unreadable. Use arrays to manage that: function getImage($image,$image_url ... https://stackoverflow.com php return inside switch case is working but return after switch ...
Add the break; statement at the end of each case . Otherwise the code of the next case s of the switch statement will be executed too. https://stackoverflow.com how to return switch case value? - Stack Overflow
<?php $opt = $_POST['product']; // $opt is value that came from your html select switch ($opt) case "28": // if the value is 28 echo(1); // you can ... https://stackoverflow.com |