patsubst subst
In fact all is explained in the doc: Finds whitespace-separated words in TEXT ... means that one or more spaces have to separate the words. ... that match ... ,$(subst ee,EE,feet on the street) substitutes the string `fEEt on the strEEt' . $(patsubst pattern , replacement , text ): Finds whitespace-separated words in text that ...
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 patsubst subst 相關參考資料
AIdrifter CS 浮生筆錄Makefile 字串處理常見語法- HackMD
Makefile 字串處理常見語法. 一般字串處理. subst. $(subst <from>,<to>,<text>) ... patsubst. $(patsubst <pattern>,<replacement>,<text>). 名稱：模式字符串替換 ... https://hackmd.io Function "patsubst" in Makefile - Stack Overflow
In fact all is explained in the doc: Finds whitespace-separated words in TEXT ... means that one or more spaces have to separate the words. ... that match ... https://stackoverflow.com GNU make - Functions for Transforming Text
$(subst ee,EE,feet on the street) substitutes the string `fEEt on the strEEt' . $(patsubst pattern , replacement , text ): Finds whitespace-separated words in text that ... https://ftp.gnu.org GNU make - Text Functions - FTP
$(subst ee,EE,feet on the street) substitutes the string `fEEt on the strEEt' . $(patsubst pattern , replacement , text ): Finds whitespace-separated words in text that ... https://ftp.gnu.org linux makefile字符串操作函数替换subst、模式替换patsubst ...
2017年12月19日 — 名称：模式字符串替换函数——patsubst。 功能：以通配符的形式替换字符，查找<text>中的单词（单词以“空格”、“Tab”或“回 ... https://www.cnblogs.com Makefile字串函式的用法 - 雜記
2008年3月1日 — $(subst ee,EE,feet on the street)， 把「feet on the street」中的「ee」替換成「EE」，返回結果是「fEEt on the strEEt」。 $(patsubst <pattern> ... http://deanjai.blogspot.com Makefile用法(字串函式) - 雜記
2006年3月23日 — $(subst ee,EE,feet on the street)， 把「feet on the street」中的「ee」替換成「EE」，返回結果是「fEEt on the strEEt」。 $(patsubst <pattern> ... http://deanjai.blogspot.com Text Functions (GNU make) - GNU.org
$(subst ee,EE,feet on the street). produces the value ' fEEt on the strEEt '. $(patsubst pattern , replacement , text ). Finds whitespace-separated words in text that ... https://www.gnu.org 使用函数— 跟我一起写Makefile 1.0 文档
comma:= , empty:= space:= $(empty) $(empty) foo:= a b c bar:= $(subst $(space) ... 那么， $(objects:.o=.c) 和 $(patsubst %.o,%.c,$(objects)) 是一样的。 https://seisman.github.io |