java uuid stackoverflow
There are different methods of UUID generation. The kind you're using is behaving exactly as it should. You're using nameUUIDFromBytes , a ..., There is no guarantee that the numbers will be unique, however it is extremely improbable that a duplicate will ever be generated because ...
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 java uuid stackoverflow 相關參考資料
java - Application Generate UUID? - Stack Overflow
http://developer.android.com/reference/java/util/UUID.html and maybe if there is another site other than android developer where i can understand or see ... https://stackoverflow.com How to produce a True UUID in Java? - Stack Overflow
There are different methods of UUID generation. The kind you're using is behaving exactly as it should. You're using nameUUIDFromBytes , a ... https://stackoverflow.com unique Number generation by UUID in Java ? - Stack Overflow
There is no guarantee that the numbers will be unique, however it is extremely improbable that a duplicate will ever be generated because ... https://stackoverflow.com Java UUID generation - Stack Overflow
The UUID that an operating system will generate reserves the right to blend in information from the machine along with the time information &c. https://stackoverflow.com Android and Java Uuid - Stack Overflow
Assuming you're using the java.util.UUID's randomUUID() function there's a theoretical chance of duplication, but it's incredibly remote. The ids ... https://stackoverflow.com Repeated set of UUIDs from java's UUID.randomUUID() - Stack Overflow
From JDK 1.6 source, indeed, UUID.randomUUID() feeds on a java.util.SecureRandom instance. If you got a repeated sequence of UUID, then ... https://stackoverflow.com Efficient method to generate UUID String in JAVA (UUID.randomUUID ...
Ended up writing something of my own based on UUID.java implementation. Note that I'm not generating a UUID, instead just a random 32 bytes hex string in ... https://stackoverflow.com How good is Java's UUID.randomUUID? - Stack Overflow
UUID uses java.security.SecureRandom , which is supposed to be "cryptographically strong". While the actual implementation is not specified ... https://stackoverflow.com |