ds dq t
1/T = dS/dQ, which appears to me that to indicate that at smaller temperature, it is "easier" to increase the entropy of a system. Easier in this ...,T dq ds ≥. 4.2 Entropy. Entropy is a state function defined by (per unit mass). The second law defines entropy as a state function (see Petty, Section 6.1) and.
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 ds dq t 相關參考資料
Ch.14 熵
對不可逆過程而言， đQ ≤ T dS （比可逆時多了微觀態）且đW ≥ -p dV （功 ... 除了自熱力學方式dS = dQrev / T 定義熵之外，我們可透過統計來定義熵，想法如下：. http://boson4.phys.tku.edu.tw Entropy, why dS = dQ T | Physics Forums
1/T = dS/dQ, which appears to me that to indicate that at smaller temperature, it is "easier" to increase the entropy of a system. Easier in this ... https://www.physicsforums.com Second Law of Thermodynamics
T dq ds ≥. 4.2 Entropy. Entropy is a state function defined by (per unit mass). The second law defines entropy as a state function (see Petty, Section 6.1) and. https://www.nsstc.uah.edu thermodynamics - For change in entropy dS = dqT, is T the ...
If the heat is transferred reversibly, the temperatures of the two bodies have to be the same. Transfer of heat from hotter to colder body is ... https://physics.stackexchange. thermodynamics - What ds>dQT mean? - Physics Stack Exchange
There is something they forgot to mention in your notes (either from ignorance, or out of omission). The temperature within the system is spatially non-uniform ... https://physics.stackexchange. Why is ds=dQT ? | Physics Forums
I don't understand how this measures the disorder of a system. https://www.physicsforums.com 大學物理相關內容討論:entropy 的計算 - 國立臺灣師範大學物理學系
以上兩項互相有關聯因此定義 dS= dQ/T = nCv/T dT + nR/V dV 這時候兩項的係數都是常數因此可分別積分互不影響而得出ΔS= n Cv ln(Tf/Ti)+ nR ... http://www.phy.ntnu.edu.tw 大學物理相關內容討論:熵的明確物理意義 - 國立臺灣師範大學物理學系
但我課本看很久卻看不出dS=dQ/T有什麼物理意義存在. 1.可否針對dS=dQ/T這個很重要的概念做個明確物理解釋. 2.還有不可逆的行為中熵會變大. http://www.phy.ntnu.edu.tw 熵 - 教育百科 - 教育雲
由熱力學第二定律可得，在不可逆過程中，熵值的變化(dS)是體系從環境中吸收（或放出）的熱量(dQ)除以體系的絕對溫度(T)，即dS=dQ/ T。由此可知，當吸收（或放出） ... https://pedia.cloud.edu.tw 熵與熱力學第二定律
定義一個新的狀態函數熵(Entropy) S，其變化是ΔS = Sf - Si = ∫if dQ/T ... 其中dW = F dx，dx 是伸長量，dQ = T dS（因為ΔS = Q/T，故dS = dQ/T ，即固定溫度的Q 與S ... http://boson4.phys.tku.edu.tw |