build gradle output outputfile
（1）在專案app下的build.gradle中的android標籤中做如下配置：. android. ... output.outputFile = new File(outputFile.parent, fileName), 今天升级了Android Studio，自然而然也就升级Gradle（3.2.1 –> 3.3.0），于是乎，出现了 ... versionCode}.apk" } output.outputFileName = fileName
| 相關軟體 Android Studio 資訊 | |
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 build gradle output outputfile 相關參考資料
Android Studio 3.0 - Fix apk naming issue when upgrading to ...
Android Studio 3.0 - Fix apk naming issue when upgrading to Gradle 3.0.0. ... output.outputFile.parent, output.outputFile.name.replace(".apk" ... https://medium.com android studio 3.0 升級問題,遇到的坑； - IT閱讀 - ITREAD01.COM
（1）在專案app下的build.gradle中的android標籤中做如下配置：. android. ... output.outputFile = new File(outputFile.parent, fileName) https://www.itread01.com Android 解决API 'variantOutput.getPackageApplication()' is ...
今天升级了Android Studio，自然而然也就升级Gradle（3.2.1 –> 3.3.0），于是乎，出现了 ... versionCode}.apk" } output.outputFileName = fileName https://objectville.github.io Cannot set the value of read-only property 'outputFile' - Stack ...
outputFileName instead of output. ... So when Studio asks (when you open your project for the first time) you to update Gradle to support instant ... https://stackoverflow.com Gradle 3.0.0设置Apk文件输出命名- 简书
修改生成的apk名字 android applicationVariants.all variant -> if (variant.buildType.name.equals('release')) variant.outputs.each output -> def parent = '. ... Error:(26, 0) Cannot set th... https://www.jianshu.com Gradle Version 4.6 - Absolute path are not supported when ...
android.applicationVariants.all variant -> variant.outputs.all output -> def fileName ... versionName}.apk" outputFileName = new File(output. https://stackoverflow.com How to set versionName in APK filename using gradle ...
The above solution has been tested with the following Android Gradle Plugin Versions: 3.5.2 (November 2019) ... outputFile = new File( output.outputFile.parent ... https://stackoverflow.com [Android] Android Gradle 3.0.0 plugin, Cannot set the value of ...
Use outputFileName instead of output.outputFile if you change only file name (that is your case). Example from the guide: // If you use each() to ... https://stackoverflow.max-ever |