Python class NameError: name is not defined

You need to make an instance of the class to use its methods first: client = Client('192.168.1.94','root&#3...

Python class NameError: name is not defined

You need to make an instance of the class to use its methods first: client = Client('192.168.1.94','root','root') client.addClient('192.168.1.95' ..., Your code is correct, but I suspect there is something wrong with the indentation. This is how it should be class Agent: def hello(self, ...

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Python class NameError: name is not defined 相關參考資料
"Python NameError: name is not defined" for class - Stack ...

It's simple. You have defined the main as a Question class' method, but I guess it should be just a function, so move it one indentation level to the left and it's ...

https://stackoverflow.com

Name is not defined in Python - Stack Overflow

You need to make an instance of the class to use its methods first: client = Client('192.168.1.94','root','root') client.addClient('192.168.1.95' ...

https://stackoverflow.com

NameError: class name is not defined - Stack Overflow

Your code is correct, but I suspect there is something wrong with the indentation. This is how it should be class Agent: def hello(self, ...

https://stackoverflow.com

NameError: name 'Class' is not defined - Stack Overflow

Forward declaration doesn't work in Python. So you'll get an error only if you create an object of the Main class as follows: class Main: def ...

https://stackoverflow.com

Python class NameError. Var is not defined - Stack Overflow

If you want your variables to be visible within the scope of your class functions, pass self into every class function and use your class variables ...

https://stackoverflow.com

python className not defined NameError - Stack Overflow

The problem is that your if __name__ == "__main__" block is inside of your class definition. This will cause an error, as the code within the if will be run as part of ...

https://stackoverflow.com

Python NameError: name '...' is not defined in a class - Stack ...

The variable options is likely intended to maintain a reference to the available options. What it's doing instead is calling the method itself before ...

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Python NameError: name is not defined - Stack Overflow

Define the class before you use it: class Something: def out(self): print("it works") s = Something() s.out(). You need to pass self as the first ...

https://stackoverflow.com