Bertrand theorem

由 PD Leenheer 著作 · 2023 · 被引用 1 次 — A cornerstone result in Newtonian mechanics is Bertrand's Theorem concerning t...

Bertrand theorem

由 PD Leenheer 著作 · 2023 · 被引用 1 次 — A cornerstone result in Newtonian mechanics is Bertrand's Theorem concerning the behavior of the solutions of the classical two-body problem. ,Bertrand's theorem1 proves that for a central force power-law potential energy V(r) ~ rn, closed orbits exist only for n = ─1 and +2.

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Bertrand theorem 相關參考資料
(PDF) The Bertrand Theorem Revisited

2024年1月13日 — The Bertrand theorem, which states that the only power-law central potentials for which the bounded trajectories are closed are 1/r2 and r2, ...

https://www.researchgate.net

A Comprehensive Proof of Bertrand's Theorem

由 PD Leenheer 著作 · 2023 · 被引用 1 次 — A cornerstone result in Newtonian mechanics is Bertrand's Theorem concerning the behavior of the solutions of the classical two-body problem.

https://epubs.siam.org

An Even Simpler “Truly Elementary” Proof of Bertrand's ...

Bertrand's theorem1 proves that for a central force power-law potential energy V(r) ~ rn, closed orbits exist only for n = ─1 and +2.

https://www.spsnational.org

Bertrand's postulate

In number theory, Bertrand's postulate is the theorem that for any integer n · A less restrictive formulation is: for every n · His conjecture was completely ...

https://en.wikipedia.org

Bertrand's Theorem

2013年1月18日 — Joseph Louis François Bertrand proved that there are only two central force fields that give rise to bounded orbits, the inverse-square law ...

https://jfuchs.hotell.kau.se

Bertrand's theorem - Wikipedia

https://en.wikipedia.org

Bertrand's Theorem -- from Eric Weisstein's World of Physics

A theorem first formulated by Sturm (1841) and related to the least curvature principle of Heinrich Hertz Eric Weisstein's World of Biography and Gauss.

https://scienceworld.wolfram.c

Bertrand's Theorem | Lec 07 - YouTube

https://www.youtube.com

Proof of Bertrand's Theorem*

principal conclusion of Bertrand's theorem. Substituting Eqs. (A-13a, b) and. (A-15) into Eq. (A-13c) yields the condition. P2(1 - P2)(4 - P2) = 0. (A- 16).

http://scipp.ucsc.edu

說明

https://zh.wikipedia.org