: binary operator expected
And when it sees four arguments, with the first one a ! , [ expects to see something like [ ! arg1 op arg2 ] where op is a binary operator. (this ...,字符串判空有空格报错：binary operator expected. 2016年09月02日14:23:52 xinwendewen 阅读数：8410. 使用 -z 或 -n 对一个变量判空时，需要注意若直接使用 [ -n ...
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 : binary operator expected 相關參考資料
Binary Operator Expected error in Shell Script - LinuxQuestions.org
I am comparing numbers in a file by shell script. Following anippet of my code gave me line 22: [: –lt: binary operator expected Error. Code: https://www.linuxquestions.org bash - Binary operator expected - quoting question for shell ...
And when it sees four arguments, with the first one a ! , [ expects to see something like [ ! arg1 op arg2 ] where op is a binary operator. (this ... https://unix.stackexchange.com 字符串判空有空格报错：binary operator expected - zwt0909的博客 ...
字符串判空有空格报错：binary operator expected. 2016年09月02日14:23:52 xinwendewen 阅读数：8410. 使用 -z 或 -n 对一个变量判空时，需要注意若直接使用 [ -n ... https://blog.csdn.net 脚本报错： binary operator expected - Superxgl的专栏- CSDN博客
shell脚本启动：字符串判空有空格报错：binary operator expected. u014252478 63 ... Linux下单分支if语句下unary operator expected错误解决方法. https://blog.csdn.net bash - Script error: –le: binary operator expected - Ask Ubuntu
The source of the error: [: –le: binary operator expected is the fact you are using the unicode version of – instead of the regular -. Note: The ... https://askubuntu.com binary operator expected error when checking if a file with full ...
Looks like your $pathname includes more than one word. Could be multiple lines in your .rm.cfg file, or perhaps the path includes spaces. https://stackoverflow.com Bash - binary operator expected - Stack Overflow
Use double straight braces instead of ones as follows since you r using extended expressions. if [[ ! -f "$BASE_DIR/$i"* ]];. Need to check with ... https://stackoverflow.com Unix bash error - binary operator expected - Stack Overflow
Doing it another way: just ask how many parameters were passed: ... if [ $# -eq 0 ] ... You get the error in your code because the $@ variable ... https://stackoverflow.com |