mongodb remove by id
justOne, boolean, Optional. To limit the deletion to just one document, set to true . Omit to use the default value of false and delete all documents matching the ... ,In mongodb each document must be unique, so you need an unique field to be used as id. If you do not provide one, mongodb will provide one for you ...
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 mongodb remove by id 相關參考資料
Delete Documents — MongoDB Manual - MongoDB Documentation
Remove Only One Document that Matches a Condition. To delete at most a single document that match a specified filter,even though multiple documents may match the specified filter, use either the db.co... https://docs.mongodb.com db.collection.remove() — MongoDB Manual
justOne, boolean, Optional. To limit the deletion to just one document, set to true . Omit to use the default value of false and delete all documents matching the ... https://docs.mongodb.com How to remove _id in MongoDB and replace with another field as a ...
In mongodb each document must be unique, so you need an unique field to be used as id. If you do not provide one, mongodb will provide one for you ... https://stackoverflow.com Remove document by id field in mongodb using C# - Stack Overflow
Try below code, and see whether is working? var query = Query.EQ("_id", new BsonObjectId("objectID"));. Or var query = Query.EQ("_id", name); records. https://stackoverflow.com How to remove one 'document' by 'ID' using the Official C# Driver ...
That's the way you do it. I'm sure you know this, but if you want to put it on one line you could combine it so you don't need to define a query variable: collection. https://stackoverflow.com Remove by _id in MongoDB console - Stack Overflow
The answer is that the web console/shell at mongodb.org behaves differently and not ... db.foo.remove(**_id**: new ObjectId("4f872685a64eed5a980ca536")}). https://stackoverflow.com Remove record by id? - Stack Overflow
You need to pass the _id value as an ObjectID, not a string: var mongodb = require('mongodb'); db.collection('posts', function(err, collection) collection. https://stackoverflow.com |